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7v^2+47v+30=0
a = 7; b = 47; c = +30;
Δ = b2-4ac
Δ = 472-4·7·30
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-37}{2*7}=\frac{-84}{14} =-6 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+37}{2*7}=\frac{-10}{14} =-5/7 $
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